650=2*(5+x^2+x^2)

Solution for 650=2*(5+x^2+x^2) equation:

650=2(5+x^2+x^2)

We move all terms to the left:

650-(2(5+x^2+x^2))=0


We calculate terms in parentheses: -(2(5+x^2+x^2)), so:

2(5+x^2+x^2)

We multiply parentheses

2x^2+2x^2+10

We add all the numbers together, and all the variables

4x^2+10

Back to the equation:

-(4x^2+10)


We get rid of parentheses

-4x^2-10+650=0

We add all the numbers together, and all the variables

-4x^2+640=0

a = -4; b = 0; c = +640;
Δ = b2-4ac
Δ = 02-4·(-4)·640
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{10}}{2*-4}=\frac{0-32\sqrt{10}}{-8}
=-\frac{32\sqrt{10}}{-8}
=-\frac{4\sqrt{10}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{10}}{2*-4}=\frac{0+32\sqrt{10}}{-8}
=\frac{32\sqrt{10}}{-8}
=\frac{4\sqrt{10}}{-1}
$